A) \[\frac{77}{8}c{{m}^{2}}\]
B) \[\frac{67}{8}c{{m}^{2}}\]
C) \[\frac{83}{8}c{{m}^{2}}\]
D) \[\frac{55}{8}c{{m}^{2}}\]
Correct Answer: A
Solution :
| [a] Let r be the radius of the circle. |
| Circumference \[=22cm\] |
| \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2\pi r=22\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,r=\frac{22}{2\pi }=\frac{11}{\pi }\] |
| Area of quadrant of the circle \[=\frac{1}{4}\times \pi \times {{r}^{2}}\] |
| \[=\frac{1}{4}\times \pi \times {{\left( \frac{11}{\pi } \right)}^{2}}=\frac{1}{4}\times \pi \times \frac{{{11}^{2}}}{{{\pi }^{2}}}\] |
| \[=\frac{121\times 7}{4\times 22}=\frac{77}{8}c{{m}^{2}}\] |
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