A) \[2\pi c{{m}^{2}}\]
B) \[4\pi c{{m}^{2}}\]
C) \[8\pi c{{m}^{2}}\]
D) \[16\pi c{{m}^{2}}\]
Correct Answer: C
Solution :
| [c] \[r=\frac{8}{2}=4\,cm\] |
| \[\therefore \] Area \[=\frac{1}{2}\pi {{r}^{2}}=\frac{1}{2}\pi {{(4)}^{2}}=8\pi \,c{{m}^{2}}\] |
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