A) \[d_{1}^{2}+d_{2}^{2}={{d}^{2}}\]
B) \[{{d}_{1}}+{{d}_{2}}=d\]
C) \[{{d}_{1}}+{{d}_{2}}>d\]
D) \[{{d}_{1}}+{{d}_{2}}<d\]
Correct Answer: B
Solution :
[b] \[\pi {{d}_{1}}+\pi {{d}_{2}}=\pi d\] \[{{d}_{1}}+{{d}_{2}}=d\]
You need to login to perform this action.
You will be redirected in
3 sec
