A) \[\text{9}.\text{42 c}{{\text{m}}^{\text{2}}}\]
B) \[\text{1}0.\text{32 c}{{\text{m}}^{\text{2}}}\]
C) \[\text{1}0.\text{58 c}{{\text{m}}^{\text{2}}}\]
D) \[\text{11}.\text{52 c}{{\text{m}}^{\text{2}}}\]
Correct Answer: A
Solution :
| [a] Given, radius of the circle \[(r)=6cm\] |
| and central angle \[(\theta )=30{}^\circ \] |
| \[\therefore \] Area of the sector \[=\frac{\theta }{360{}^\circ }\times \pi {{r}^{2}}\] |
| \[=\frac{30{}^\circ }{360{}^\circ }\times 3.14\times {{(6)}^{2}}\] |
| \[=\frac{1}{12}\times 3.14\times 36=9.42c{{m}^{2}}\] |
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