A) \[\text{79}.\text{5 cm}\]
B) \[\text{81}.\text{5 cm}\]
C) \[\text{83}.\text{4 cm}\]
D) \[\text{88}.\text{5 cm}\]
Correct Answer: B
Solution :
| [b] Area of sector |
| \[=240/360\times \pi {{(100)}^{2}}=20933c{{m}^{2}}\] |
| Let r be the radius of the new circle, then |
| \[20933=\pi {{r}^{2}}\] |
| \[r=\sqrt{\frac{20933}{\pi }}=81.5\,cm\] |
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