A) hexanoic acid
B) gluconic acid
C) saccharic acid
D) bromohexane.
Correct Answer: B
Solution :
\[\underset{\begin{smallmatrix} |\\ C{{H}_{2}}OH \end{smallmatrix}}{\overset{\begin{smallmatrix} CHO\\ | \end{smallmatrix}}{\mathop{{{\left( CHOH \right)}_{4}}}}}\,\xrightarrow{B{{r}_{2}}-water}\underset{\begin{smallmatrix} |\\ C{{H}_{2}}OH \\ Gluconic\,acid \end{smallmatrix}}{\overset{\begin{smallmatrix} COOH\\ | \end{smallmatrix}}{\mathop{{{\left( CHOH \right)}_{4}}}}}\,\]
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