A) \[\sqrt{{{a}^{2}}+{{b}^{2}}}\] units
B) \[\frac{1}{2}\sqrt{{{a}^{2}}+{{b}^{2}}}\] units
C) \[2\sqrt{{{a}^{2}}+{{b}^{2}}}\] units
D) \[\sqrt{a+b}\] units
Correct Answer: C
Solution :
[c] Distance between \[(a,b)\]and \[(-a,-b)\] is given by |
\[d=\sqrt{{{(-a-a)}^{2}}+{{(-b-b)}^{2}}}\] |
\[=\sqrt{{{(-2a)}^{2}}+{{(-2b)}^{2}}}=\sqrt{4{{a}^{2}}+4{{b}^{2}}}=2\sqrt{{{a}^{2}}+{{b}^{2}}}\]units. |
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