A) 0
B) 1
C) 2
D) 3
Correct Answer: C
Solution :
Since, A and 5 lie on the circle having centre O. OA=OB |
\[\Rightarrow \,\,\sqrt{{{\left( 4-2 \right)}^{2}}+{{\left( 3-3 \right)}^{2}}}=\sqrt{{{\left( x-2 \right)}^{2}}+{{\left( 5-3 \right)}^{2}}}\] |
\[\Rightarrow \,\,\,\,2=\sqrt{{{\left( x-2 \right)}^{2}}+4}\] |
\[\Rightarrow \,\,\,4={{\left( x-2 \right)}^{2}}+4\] |
\[\Rightarrow \,\,\,\,{{\left( x-2 \right)}^{2}}=0\] |
\[\Rightarrow \,\,\,\,x=2\] |
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