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10th Class Mathematics Coordinate Geometry Question Bank MCQs - Coordinate Geometry

  • question_answer
    The perimeter of the triangle formed by the points \[(0,0),\]\[(2,0),\] and \[(2,2)\] is:

    A) \[1-2\sqrt{2}\]

    B) \[2\sqrt{2}+1\]

    C) \[4+\sqrt{2}\]

    D) \[4+2\sqrt{2}\]

    Correct Answer: D

    Solution :

    [d] Let \[A(0,0),\]\[B(2,0)\] and \[C(0,2)\] be the vertices of \[\Delta ABC\]
    \[\therefore \,\,\,\,\,\,\,\,\,\,AB=\sqrt{{{(2-0)}^{2}}+{{(0-0)}^{2}}}=2\]
    \[BC=\sqrt{{{(0-2)}^{2}}+{{(2-0)}^{2}}}=2\sqrt{2}\]
    \[CA=\sqrt{{{(0-0)}^{2}}+{{(0-2)}^{2}}}=2\]
    \[\therefore \]Required perimeter
    \[=2+2\sqrt{2}+2=4+2\sqrt{2}\]


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