A) \[{{C}_{3}}{{H}_{7}}Br\]
B) \[{{C}_{4}}{{H}_{9}}Br\]
C) \[{{C}_{2}}{{H}_{5}}Br\]
D) \[{{C}_{5}}{{H}_{11}}Br\]
Correct Answer: C
Solution :
\[{{C}_{2}}{{H}_{5}}Br+KCN\to \underset{\Pr opane\,nitrile}{\mathop{{{C}_{2}}{{H}_{5}}CN}}\,+KBr\]
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