question_answer

Consider the following reaction and identify X and Y. \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}I\xrightarrow{alc.\,KOH}X\xrightarrow{B{{r}_{2}}}Y\]

A)

X	Y
\[C{{H}_{3}}CH=C{{H}_{2}}\]

B)

X	Y
\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\]	\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\]

C)

X	Y

D)

X	Y
\[C{{H}_{3}}CH=C{{H}_{2}}\]	\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\]

Correct Answer: A

Solution :

\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}l\xrightarrow{KOH\,(alc.)}C{{H}_{3}}-\underset{X}{\mathop{CH=C{{H}_{2}}}}\,\]