A) \[\sec A\]
B) \[\sin A\]
C) \[\cos ecA\]
D) \[\cos A\]
Correct Answer: B
Solution :
| [b]\[(\cos ec\,A+\cot A)\,(1-\cos A)\] |
| \[=\left( \frac{1}{\sin A}+\frac{\cos A}{\sin A} \right)\,\,(1-\cos A)\] |
| \[=\left( \frac{1+\cos A}{\sin A} \right)\,\,\,(1-\cos A)=\frac{1-{{\cos }^{2}}A}{\sin A}=\frac{{{\sin }^{2}}A}{\sin A}=\sin A\] |
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