| In the given figure, if \[AB=14cm,\] then the value of tan B is:(CBSE 2012) |
 |
A) \[\frac{4}{3}\]
B) \[\frac{14}{3}\]
C) \[\frac{5}{3}\]
D) \[\frac{13}{3}\]
Correct Answer: A
Solution :
| [a] \[AC=\sqrt{{{13}^{2}}-{{5}^{2}}}=12\,cm\] |
| \[DE=AC=12\,cm,\] |
| \[BE=AB-AE=14cm-5cm=9cm\] |
| In \[\Delta BED,\]\[\tan B=\frac{DE}{BE}=\frac{12}{9}=\frac{4}{3}\] |
You need to login to perform this action.
You will be redirected in
3 sec
