A) \[2\]
B) \[-2\]
C) \[-\frac{1}{2}\]
D) \[\frac{1}{2}\]
Correct Answer: D
Solution :
| [d] We have, |
| \[{{\tan }^{2}}45{}^\circ -{{\cos }^{2}}30{}^\circ =x\sin 45{}^\circ \cos 45{}^\circ \] |
| \[\Rightarrow \,\,\,\,\,\,\,\,{{1}^{2}}-{{\left( \frac{\sqrt{3}}{2} \right)}^{2}}=x\left( \frac{1}{\sqrt{2}} \right)\,\,\left( \frac{1}{\sqrt{2}} \right)\,\,\,\Rightarrow \,\,1-\frac{3}{4}=\frac{x}{2}\] \[\Rightarrow \ \ \frac{1}{4}=\frac{x}{2}\ \ \ \ \Rightarrow x=2\times \frac{1}{4}=\frac{1}{2}\] |
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