A) \[\sqrt{3}\]
B) \[0\]
C) \[\frac{1}{\sqrt{3}}\]
D) \[1\]
Correct Answer: B
Solution :
| [b] We have, \[\tan \alpha =\sqrt{3}\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\alpha =60{}^\circ \] \[[\tan 60{}^\circ =\sqrt{3}]\] |
| Again, \[\tan \beta =\frac{1}{\sqrt{3}}\,\,\,\,\Rightarrow \,\,\,\,\beta =30{}^\circ \]\[\left[ \tan 30{}^\circ =\frac{1}{\sqrt{3}} \right]\] |
| \[\therefore \,\,\,\,\,\,\,\alpha +\beta =60{}^\circ +30{}^\circ =60{}^\circ \] |
| \[\therefore \,\,\,\cot (\alpha +\beta )=cot90{}^\circ =0\] |
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