A) \[0{}^\circ \]
B) \[30{}^\circ \]
C) \[60{}^\circ \]
D) \[90{}^\circ \]
Correct Answer: D
Solution :
[d] Given, \[\sin \alpha =\frac{1}{2}\,\,\,\,\,\,\,\,\,\,\,\Rightarrow \,\,\,\,\,\,\,\alpha =30{}^\circ \] \[\left[ \sin 30{}^\circ =\frac{1}{2} \right]\] |
and \[\cos \beta =\frac{1}{2}\,\,\,\,\,\,\,\,\,\,\,\,\,\Rightarrow \,\,\,\beta =60{}^\circ \] \[\left[ \cos 60{}^\circ =\frac{1}{2} \right]\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\alpha +\beta =30{}^\circ +60{}^\circ =90{}^\circ \] |
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