A) \[{{\tan }^{4}}A-{{\tan }^{2}}A\]
B) \[{{\tan }^{2}}A+{{\tan }^{4}}A\]
C) \[{{\tan }^{2}}A-{{\tan }^{4}}A\]
D) None of these
Correct Answer: B
Solution :
[b] We have, \[({{\sec }^{4}}A-{{\sec }^{2}}A)\] |
\[={{\sec }^{2}}A({{\sec }^{2}}A-1)={{\sec }^{2}}A(1+{{\tan }^{2}}A-1)\] |
\[={{\sec }^{2}}A{{\tan }^{2}}A=(1+{{\tan }^{2}}A){{\tan }^{2}}A=({{\tan }^{2}}A+{{\tan }^{4}}A)\] |
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