A) \[-15\]
B) \[\frac{-5}{2}\]
C) \[\frac{2}{7}\]
D) None of the above
Correct Answer: A
Solution :
Given, pair of linear equations is |
\[kx-5y-2=0\]and \[6x+2y-7=0\] |
Here, \[{{a}_{1}}=k,\,{{b}_{1}}=-5,\,{{c}_{1}}=-2\] |
and \[{{a}_{2}}=6,\,{{b}_{2}}=2,\,{{c}_{2}}=-7\] |
On comparing with standard form of pair of linear equations we get, |
For no solution, |
\[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}\ne \frac{{{c}_{1}}}{{{c}_{2}}}\]\[\Rightarrow \,\frac{k}{6}=\frac{-5}{2}\ne \frac{-2}{-7}\] |
\[\Rightarrow \,\,\,\frac{k}{6}=-\frac{5}{2}\,\,\Rightarrow k=-15\] |
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