A) 10
B) -10
C) -7
D) -2
Correct Answer: B
Solution :
Given, 2 is the zero of the quadratic polynomial. We have, |
\[f\left( x \right)={{x}^{2}}+3x+k\] |
\[f\left( 2 \right)=0\] |
\[\Rightarrow \,{{\left( 2 \right)}^{2}}+3\times 2+k=0\] |
\[\Rightarrow \,\,4+6+k=0\] |
\[\Rightarrow k=-10\]. |
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