The value of Henry's law constant for some gases at 293 K is given below. Arrange the gases in the increasing order of their solubility. |
He : 144.97 k bar, \[{{H}_{2}}:\text{ }69.16\text{ }k\,bar\], |
\[{{N}_{2}}:\text{ }76.48\text{ }k\,bar\], \[{{O}_{2}}:\text{ }34.86\text{ }k\,bar\] |
A) \[He<{{N}_{2}}<{{H}_{2}}<{{O}_{2}}\]
B) \[{{O}_{2}}<{{H}_{2}}<{{N}_{2}}<He\]
C) \[{{H}_{2}}<{{N}_{2}}<{{O}_{2}}<He\]
D) \[He<{{O}_{2}}<{{N}_{2}}<{{H}_{2}}\]
Correct Answer: A
Solution :
Higher the value of \[{{K}_{H}}\], lower is its solubility of gas in the liquid.You need to login to perform this action.
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