A) It has oxidation state of +6.
B) The hybridisation involved in \[Xe{{F}_{6}}\]is \[s{{p}^{3}}{{d}^{3}}\]
C)
The shape of \[Xe{{F}_{6}}\]is distorted octahedral and can be represented as 
D) On hydrolysis it gives Xe, HF and\[{{O}_{2}}\].
Correct Answer: D
Solution :
On hydrolysis the products formed are \[Xe{{O}_{3}}\]and HF. \[Xe{{F}_{6}}+3{{H}_{2}}O\to Xe{{O}_{3}}+6HF\]
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