A) \[{{N}_{2}}O<NO<N{{O}_{2}}<NO_{3}^{-}<NH_{4}^{+}\]
B) \[NH_{4}^{+}<{{N}_{2}}O<NO<N{{O}_{2}}<NO_{3}^{-}\]
C) \[NH_{4}^{+}<{{N}_{2}}O<N{{O}_{2}}<NO_{3}^{-}<NO\]
D) \[NH_{4}^{+}<NO<{{N}_{2}}O<N{{O}_{2}}<NO_{3}^{-}\]
Correct Answer: B
Solution :
\[{{N}_{2}}O=+1,\,NO=+2,\,N{{O}_{2}}=+4,\,NO_{3}^{-}=+5,\,NH_{4}^{+}=-3\]Increasing order of oxidation state will be \[NH_{4}^{+}<{{N}_{2}}O<NO<N{{O}_{2}}<NO_{3}^{-}\]You need to login to perform this action.
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