| Complete the given equations |
| (i) \[Mg+2HN{{O}_{3}}\to Mg{{(N{{O}_{3}})}_{2}}\]+ W |
| (ii) \[Cu+8HN{{O}_{3}}\to 3Cu{{(N{{O}_{3}})}_{2}}+\]....X...\[4{{H}_{2}}O\] |
| (iii) \[8N{{H}_{3}}+3C{{l}_{2}}\to \] Y ..+\[{{N}_{2}}\](excess) |
| (iv) \[{{I}_{2}}+10HN{{O}_{3}}\to \] Z \[10N{{O}_{2}}+4{{H}_{2}}O\] |
A)
W X Y Z NO \[2N{{O}_{2}}\] \[6NC{{l}_{3}}\] \[5HI{{O}_{3}}\]
B)
W X Y Z \[{{H}_{2}}\] 2NO \[6N{{H}_{4}}Cl\] \[2HI{{O}_{3}}\]
C)
W X Y Z \[{{N}_{2}}\] \[{{N}_{2}}O\] \[NC{{l}_{3}}\] HI
D)
W X Y Z \[N{{O}_{2}}\] \[{{N}_{2}}O\] \[2N{{H}_{4}}Cl\] 3HI
Correct Answer: B
Solution :
| (i)\[Mg+\underset{(very\,dilute)}{\mathop{2HN{{O}_{3}}}}\,\left( 5% \right)\to Mg{{\left( N{{O}_{3}} \right)}_{2}}+\underset{(W)}{\mathop{{{H}_{2}}}}\,\] |
| (ii) \[3Cu+\underset{(dil.)}{\mathop{8HN{{O}_{3}}}}\,\to 3Cu{{(N{{O}_{3}})}_{2}}+\underset{(X)}{\mathop{2NO}}\,+4{{H}_{2}}O\] |
| (iii) \[\underset{(exces)}{\mathop{8N{{H}_{3}}}}\,+3C{{l}_{2}}\to \underset{(Y)}{\mathop{6N{{H}_{4}}Cl}}\,+{{N}_{2}}\] |
| (iv) \[{{I}_{2}}+10HN{{O}_{3}}\to \underset{(Z)}{\mathop{2HI{{O}_{3}}}}\,+10N{{O}_{2}}+4{{H}_{2}}O\] |
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