A) aqueous solution of \[N{{H}_{3}}\] reacts with \[C{{u}^{2+}}\] ion to form deep blue coloured complex
B) \[N{{H}_{3}}\] reacts with \[C{{u}^{2+}}\] ion to give blue precipitate of CuO
C) aqueous solution of \[N{{H}_{3}}\] reacts with \[C{{u}^{2+}}\] ion to form white coloured complex
D) \[N{{H}_{3}}\] reacts with \[C{{u}^{2+}}\]ion to give green precipitate.
Correct Answer: A
Solution :
\[Cu_{(aq)}^{2+}+4N{{H}_{3(aq)}}\to \underset{Deep\,blue}{\mathop{\left[ Cu{{\left( N{{H}_{3}} \right)}_{4}} \right]_{(aq)}^{2+}}}\,\]
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