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  5. The Solid State / ठोस प्रावस्था

12th Class Chemistry The Solid State / ठोस प्रावस्था Question Bank MCQs - The Solid State

  • question_answer
    Volume occupied by single CsCl ion pair in a crystal is \[7.014\times {{10}^{-23\text{ }}}c{{m}^{3}}\]. The smallest Cs - Cs internuclear distance is equal to length of the side of the cube corresponding to volume of one CsCI ion pair. The smallest Cs to Cs internuclear distance is nearly

    A) \[4.4\overset{{}^\circ }{\mathop{A}}\,\]

    B) \[4.3\overset{{}^\circ }{\mathop{A}}\,\]

    C) \[4\overset{{}^\circ }{\mathop{A}}\,\]

    D) \[4.5\overset{{}^\circ }{\mathop{A}}\,\]

    Correct Answer: C

    Solution :

    Volume of \[CsCl={{a}^{3}}\] \[7.014\times {{10}^{-23}}c{{m}^{3}}={{a}^{3}}\] (a = edge length) \[a=\sqrt[3]{7.014\times {{10}^{-23}}}=4.12\times {{10}^{-8}}cm\] \[=4.12\overset{o}{\mathop{A}}\,\approx 4\overset{o}{\mathop{A}}\,\]


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