A) 0.94
B) 0.04
C) 0.50
D) 0.3
Correct Answer: A
Solution :
Let the fraction of metal which exists as \[N{{i}^{2+}}\] ion be x. Then the fraction of metal as\[N{{i}^{3+}}=0.98-x\] \[\therefore 2x+3(0.98-x)=2\] \[\Rightarrow 2x+2.94-3x=2\Rightarrow x=0.94\]You need to login to perform this action.
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