A) \[120{}^\circ \]
B) \[60{}^\circ \]
C) \[90{}^\circ \]
D) \[45{}^\circ \]
Correct Answer: C
Solution :
[c] Here, \[{{(AB)}^{2}}={{(6\sqrt{3})}^{2}}=108,\,\,A{{C}^{2}}={{(12)}^{2}}=144\] |
and \[{{(BC)}^{2}}={{(6)}^{2}}=36\] |
\[A{{C}^{2}}=A{{B}^{2}}+B{{C}^{2}}\] |
\[\therefore \,\,\,\,\,\Delta ABC\] is a right triangle with \[\angle B=90{}^\circ \]. |
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