A) \[\angle B=\angle E\]
B) \[\angle A=\angle D\]
C) \[\angle B=\angle D\]
D) \[\angle A=\angle F\]
Correct Answer: C
Solution :
Given, in \[\Delta ABC\] |
and \[\Delta EDF\],\[\frac{AB}{DE}=\frac{BC}{FD}\] |
By converse of basic proportionality theorem, |
\[\Delta ABC-\Delta EDF\] |
Then, \[\angle B=\angle D,\angle A=\angle E\]and \[\angle C=\angle F\] |
\[\therefore \,\,\,\,\,\angle B=\angle D\] |
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