| In the given figure, \[MN\left\| QR \right.\] and \[PM=3cm,\]\[MQ=4cm,\]\[PN=6cm,\]\[PR=x\,cm,\] then x = |
 |
A) \[8\,cm\]
B) \[6\,cm\]
C) \[10\,cm\]
D) \[14\,cm\]
Correct Answer: D
Solution :
| [d] \[MN||QR\] |
| \[\frac{PM}{MQ}=\frac{PN}{NR}\,\,\,\,\,\,\,\,\Rightarrow \,\,\,\,\frac{3}{4}=\frac{6}{NR}\,\,\,\,\,\,\,\,\,\,\Rightarrow \,\,NR=8cm\] |
| \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,x=8+6=14\,cm\] |
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