In the given figure, \[\frac{AD}{DB}=\frac{AE}{EC}\] and \[\angle ADE=70{}^\circ ,\]\[\angle BAC=50{}^\circ ,\]then angle \[\angle BCA=\] |
A) \[70{}^\circ \]
B) \[50{}^\circ \]
C) \[80{}^\circ \]
D) \[60{}^\circ \]
Correct Answer: D
Solution :
[d] \[DE||BC\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\angle ABC=70{}^\circ \] (Corresponding angles) |
Using angle sum property of triangle |
\[\angle BCA=60{}^\circ \] |
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