A) 9 cm
B) 10 cm
C) 6 cm
D) 8 cm
Correct Answer: C
Solution :
[c] Since \[\Delta ABC\tilde{\ }\Delta PQR\] |
\[\therefore \,\,\,\,\,\,\frac{ar(\Delta ABC)}{ar(\Delta PQR)}=\frac{B{{C}^{2}}}{Q{{R}^{2}}}\] |
\[\Rightarrow \,\,\,\frac{4ar(\Delta PQR)}{ar(\Delta PQR)}=\frac{{{12}^{2}}}{Q{{R}^{2}}}\] |
[Given, \[ar(\Delta ABC)=4ar(\Delta PQR)\]] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,Q{{R}^{2}}=\frac{144}{4}=36\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,QR=6\,cm\] |
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