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10th Class Mathematics Triangles Question Bank MCQs - Triangles

  • question_answer
    The areas of two similar triangles are \[\text{81 c}{{\text{m}}^{\text{2}}}\] and \[\text{49 c}{{\text{m}}^{\text{2}}}\]respectively, then the ratio of their corresponding medians is:

    A) \[7:9\]

    B) \[9:81\]

    C) \[9:7\]

    D) \[81:7\]

    Correct Answer: C

    Solution :

    [c] Given, area of two similar triangles,
    \[{{A}_{1}}=81\,c{{m}^{2}}\]
    \[{{A}_{2}}=49\,c{{m}^{2}}\]
    Ratio of corresponding medians
    \[=\sqrt{\frac{{{A}_{1}}}{{{A}_{2}}}}=\sqrt{\frac{81}{49}}=\frac{9}{7}\]


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