A) \[{{88}^{o}}C\]
B) \[{{98}^{o}}C\]
C) \[{{78}^{o}}C\]
D) \[{{32}^{o}}C\]
Correct Answer: A
Solution :
Temperature of the rod\[={{120}^{o}}C\] Amount of heat lost every minute\[={{2}^{o}}C\] \[\therefore \]Amount of heat lost for \[16\] minutes \[=16\times {{2}^{o}}C={{32}^{o}}C\] \[\therefore \]The temperature of the rod after \[16\] minutes \[={{120}^{o}}C-{{32}^{o}}C={{88}^{o}}C\]
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