question_answer

DIRECTIONS: Match Column-I with Column-II and select the correct answer using the codes given below the columns.

A)  \[A\to (t);\,B\to (s);\,C\to (r);\,D\to (p);\,E\to (q)\]

B)  \[A\to (t);\,B\to (s);\,C\to (q);\,D\to (p);\,E\to (r)\]

C)  \[A\to (s);\,B\to (t);\,C\to (p);\,D\to (q);\,E\to (r)\]

D)  \[A\to (s);\,B\to (t);\,C\to (q);\,D\to (p);\,E\to (r)\]

Correct Answer: D

Solution :

     A. As shown in the diagram below, in the isosceles right triangle, the base is bisected by the altitude and BD = AD. \[\therefore \,\,\,\,AD=15\,cm\] Area \[=\frac{1}{2}\times \] base \[\times \] height \[=\frac{1}{2}\times 30\times 15=225\,\,c{{m}^{2}}\] B. \[\frac{\sqrt{3}}{2}\times \] side \[=\sqrt{6}\] Side \[=2\sqrt{2}\,cm\]. area \[=\frac{\sqrt{3}}{4}\,\times {{(side)}^{2}}=\frac{\sqrt{3}}{4}\,\times {{(2\sqrt{2})}^{2}}\] \[=2\sqrt{3}\,c{{m}^{2}}\]. C. Let breadth \[=x\]. Length \[=x+23\]. Perimeter = 206 m. \[2(x+23+x)\,=206\] \[\therefore \,\,2x23=103\] \[x=40\] Area\[=l\times b=63\times 40\,=2520\,{{m}^{2}}\].