If the shaded portion is cut out from the whole figure then the area of remaining figure is
A) \[164\,c{{m}^{2}}\]
B) \[168\,c{{m}^{2}}\]
C) \[124\,c{{m}^{2}}\]
D) \[142\,c{{m}^{2}}\]
Correct Answer: C
Solution :
Required area = Area of DBFE + Area of DEDG \[=\left( \frac{1}{2}\times 14\times 12 \right)\,+\left( \frac{1}{2}\,\times 10\times 8 \right)\] \[=84+40\,=124\,c{{m}^{2}}\].
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