A) \[30\sqrt{7}cm\]
B) \[\frac{15\sqrt{7}}{2}cm\]
C) \[\frac{15\sqrt{7}}{4}\,cm\]
D) 30 cm
Correct Answer: C
Solution :
By Heron's formula, we have area of triangle \[=\sqrt{s(s-a)\,(s-b)\,(s-c)}\] Here, \[s=\frac{11+15+16}{2}=\frac{42}{2}=21\,cm\] \[\therefore \] Area \[=\sqrt{21(10)(6)(5)}\,=30\sqrt{7}\,sq\,cm\]. \[\therefore \] Height \[=\frac{30\sqrt{7}}{8}=\frac{15\sqrt{7}}{4}\,cm\].
You need to login to perform this action.
You will be redirected in
3 sec
