A) \[20\text{ }c{{m}^{2}}\]
B) \[10\,c{{m}^{2}}\]
C) \[\sqrt{5}\text{ }c{{m}^{2}}\]
D) \[10\sqrt{2\,}c{{m}^{2}}\]
Correct Answer: A
Solution :
| [a] \[l+b=6\,\,cm\] Then, Let, \[l=4\,\,cm\]and\[b=2\,cm\] \[\therefore \]Area of rectangle \[=l+b=4\times 2=8\,c{{m}^{2}}\] (i) According to the question, \[\frac{\text{Area}\,\text{of}\,\text{Sqare}}{\text{Area}\,\text{of}\,\text{Ractangle}}\text{=}\frac{\text{5}}{\text{2}}\] \[\Rightarrow \]Area of Square \[\text{=}\frac{5}{2}\times \]Area of Rectangle \[=\frac{5}{2}\times 8\] [From Eq. (i)] \[=5\times 4=20\,c{{m}^{2}}\] |
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