A) No change
B) 8% decrease
C) 16% decrease
D) 16% increase
Correct Answer: C
Solution :
| [c] Let the height be h and base = b. Then, area \[=\left( \frac{1}{2}\,bh \right)\]sq units New height \[=(60%\text{of}\,h)=\left( \frac{60}{100}\,h \right)=\frac{3h}{5},\] New base \[=(140%\,\text{of}\,b)=\left( \frac{140}{100}\,h \right)=\left( \frac{7b}{5} \right)\] New area \[=\left( \frac{1}{2}\times \frac{7b}{5}\times \frac{3h}{5} \right)\]sq units \[=\left( \frac{21}{50}\,bh \right)\] sq units Decrease in area \[=\left( \frac{1}{2}\,bh-\frac{21}{50}\,bh \right)=\frac{4}{50}\,bh\] Decrease percentage\[=\left( \frac{4}{50}\,bh\cdot \frac{2}{bh}\times 100 \right)=16%\] |
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