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SSC Quantitative Aptitude Mensuration Question Bank Mensuration-I (I)

  • question_answer
    The areas of two similar triangles are \[12\,c{{m}^{2}}\] and \[48\,c{{m}^{2}}.\]If the height of the smaller one is 2.1 cm, then the corresponding height of the bigger one is

    A) 0.525 cm

    B) 4.2 cm

    C) 4.41 cm

    D) 8.4 cm

    Correct Answer: B

    Solution :

    [b] The areas of two similar triangles are in the ratio of the squares of the corresponding heights. \[\frac{12}{48}=\frac{{{(2.1)}^{2}}}{{{h}^{2}}}\] \[\Rightarrow \]   \[{{h}^{2}}=4\times {{(2.1)}^{2}}\] \[\Rightarrow \]   \[h=(2\times 2.1)=4.2\,cm\]


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