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SSC Quantitative Aptitude Mensuration Question Bank Mensuration-II (II)

  • question_answer
    If the surface area of a sphere is \[346.5\,c{{m}^{2}},\]then its radius \[\left[ \text{taking}\,\pi =\frac{22}{7} \right]\]is [SSC CGL Tier II, 2014]

    A) 7 cm

    B) 3.25 cm

    C) 5.25 cm

    D) 9 cm

    Correct Answer: C

    Solution :

    [c] Surface area of sphere\[=4\pi {{r}^{2}}\] According to question,\[4{{\pi }^{2}}=346.5\] \[4\times \frac{22}{7}\times {{r}^{2}}=346.5\] \[{{r}^{2}}=\frac{346.5\times 7}{4\times 22}=27.5625\] \[r=\sqrt{27.5625;}\,\,r=5.25\]


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