A) 360 sq cm
B) 300 sq cm
C) 330 sq cm
D) 325 sq cm
Correct Answer: A
Solution :
| [a] Hypotenuse of base triangle \[=\sqrt{{{12}^{2}}+{{5}^{2}}}=\sqrt{144+25}=\sqrt{169}=13\] Perimeter of base \[=13+12+5=30\,cm\] Area of base \[=\frac{1}{2}\times 12\times 5=30\,c{{m}^{2}}\] Now, total surface area of prism \[=2\times \]Area of base + Perimeter of base \[\times \]Height \[=2\times 30+30+10=60+300=360\,c{{m}^{2}}\] |
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