A) 2.46 m
B) 3.56 m
C) 4.66 m
D) 5.76 m
Correct Answer: C
Solution :
| [c] Volume of Earth dug out \[=\pi {{r}^{2}}h=\left( \frac{22}{7}\times 5\times 5\times 14 \right){{m}^{3}}\] \[=1100\,{{m}^{2}}\] Area of embankment \[=\pi \,({{R}^{2}}-{{r}^{2}})=\frac{22}{7}\times [{{(10)}^{2}}-{{5}^{2}}]\] \[=\left( \frac{22}{7}\times 75 \right){{m}^{2}}\] Let the height of the embankment by h m. Then, \[\frac{22}{7}\times 75\times h=1100\] \[\Rightarrow \] \[h=\left( 1100\times \frac{7}{22}\times \frac{1}{75} \right)m\] \[=\frac{14}{3}m=4.66\,m\] |
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