A) 10
B) 12
C) 14
D) 15
Correct Answer: B
Solution :
In \[\Delta DAB,\,\,D{{B}^{2}}={{(3)}^{2}}+{{(4)}^{2}}\] \[\Rightarrow DB\text{ }=\text{ }5\text{ }units\] Area of \[\Delta CBD=\frac{1}{2}\times base\times height\] \[\Rightarrow \frac{1}{2}\times BC\times CD=\frac{1}{2}\times DB\times CG\] \[\Rightarrow \frac{1}{2}\times 3\times 4=\frac{1}{2}\times 5\times CG\Rightarrow CG=\frac{12}{5}\] Also, \[CG=BE=\frac{12}{5}\] \[\therefore \]Area of rectangle \[DBEF=DB\times BE\] \[=5\times \frac{12}{5}=12\]
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