A) 3.6 kg
B) 3.696 kg
C) 36 kg
D) 36.9 kg
E) None of these
Correct Answer: B
Solution :
Explanation Option [b] is correct. External radius \[=4\text{ }cm.\] Internal radius \[=3\text{ }cm,\] Volume of iron = \[\left( \frac{22}{7}\times [{{\left( 4 \right)}^{2}}-{{\left( 3 \right)}^{2}}]\times 21 \right)c{{m}^{3}}=\left( \frac{22}{7}\times 7\times 21 \right)c{{m}^{3}}=462\,c{{m}^{3}}\] \[\therefore \] Weight of iron \[=\left( 462\times 8 \right)gm=3696\text{ }gm=3.696\text{ }kg\]
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