A) 1
B) 2
C) 3
D) 4
Correct Answer: C
Solution :
Let EC = a, then \[PQ=\frac{a}{2}.\] BC and PQ are parallel. Also \[AD=DE=h,\] say \[\therefore \] Area of \[\Delta \,APQ=\frac{1}{2}\times PQ\times AD=\frac{ah}{4}\] and Area of trapezium PQCB \[=\frac{1}{2}\times DE\times (BC+PQ)\] \[=\frac{1}{2}h\left( a+\frac{a}{2} \right)=3\times \frac{ah}{4}\] \[=3\times \] Area of \[\Delta \,APQ\]You need to login to perform this action.
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