A) \[120\,\,c{{m}^{2}}\]
B) \[150\,\,c{{m}^{2}}\]
C) \[140\,\,c{{m}^{2}}\]
D) \[160\,\,c{{m}^{2}}\]
Correct Answer: B
Solution :
Area of\[\Delta S=\] \[\frac{1}{2}\times 20\times 10\,\,c{{m}^{2}}+\frac{1}{2}\times 10\times 10\,\,c{{m}^{2}}+\frac{1}{2}\times 20\times 10\,\,c{{m}^{2}}\]\[=100\,\,c{{m}^{2}}+100\,\,c{{m}^{2}}+50\,\,c{{m}^{2}}=250\,\,c{{m}^{2}}\] \[\therefore \] Area of shaded part \[=400\,\,c{{m}^{2}}-250\,\,c{{m}^{2}}=150\,\,c{{m}^{2}}\]You need to login to perform this action.
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