A) \[\frac{7\sqrt{3}}{4}sq.\,cm\]
B) \[\frac{49\sqrt{3}}{4}sq.\,cm\]
C) 35 sq. cm
D) 49 sq. cm
Correct Answer: A
Solution :
If r is the radius of the circle, then \[\pi \,{{r}^{2}}=154\] or \[{{r}^{2}}=\frac{154\times 7}{22}{{7}^{2}}\] or \[r=7\,cm\] Area of the equilateral triangle with side \[7\text{ }cm,\] \[A={{7}^{2}}\times \frac{\sqrt{3}}{4}\] \[=\frac{49\sqrt{3}}{4}\,sq.\,cm.\]
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