A) \[1080\,\,{{m}^{2}}\]
B) \[640\,\,{{m}^{2}}\]
C) \[1620\,\,{{m}^{2}}\]
D) \[2160\,\,{{m}^{2}}\]
Correct Answer: A
Solution :
Perimeter of the rectangle\[=132\,\,m\] \[=2(\ell +b)=132\,\,m\] \[=2\left( \frac{6b}{5}+b \right)=132\,\,m\] \[\Rightarrow \] \[\frac{11\,\,b}{5}=66\,\,m\] \[\Rightarrow \] \[b=\frac{66\times 5}{11}m=30\,\,m\] \[\therefore \] \[l=\frac{6\,\,b}{5}=\frac{66\times 5}{11}m=36\,\,m\] Thus, area of the rectangle \[=l\times b=\frac{6\,\,b}{5}=\frac{6\times 30}{5}=36\,\,m\]
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