A) \[\sqrt{2}(x+y)\]
B) \[2(x+y)\]
C) \[2x+2y\]
D) \[4x+2y\]
Correct Answer: A
Solution :
Diagonal of a square \[=x+y\] If a be the side of a square then \[2{{a}^{2}}={{(x+y)}^{2}}\] Also area of the square \[B=2{{a}^{2}}\] because area of \[B=2\times \] area of A. \[\therefore \] \[2{{a}^{2}}={{(x+y)}^{2}}\] \[\therefore \] Each side of the square, \[B=(x+y)\] \[\therefore \] Diagonal of the square \[=\sqrt{2}\,(x+y)\]
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