A) \[30\pi \,{{m}^{2}}\]
B) \[40\pi \,{{m}^{2}}\]
C) \[60\pi \,{{m}^{2}}\]
D) \[80\pi \,{{m}^{2}}\]
E) None of these
Correct Answer: C
Solution :
Explanation Option [c] is correct. \[l~=10\text{ }m,\text{ }h=8\text{ }m.\] So, r = \[r=\sqrt{{{\ell }^{2}}-{{h}^{2}}}=\sqrt{{{\left( 10 \right)}^{2}}-{{8}^{2}}}=6m\] \[\therefore \] Curved surface area = \[\pi r\ell =\left( \pi \times 6\times 10 \right){{m}^{2}}=60\pi \,\,{{m}^{2}}\]
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